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Old 01-14-2013, 02:09 PM #22
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I thought E=mv^2 only works with quantum calculations.
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Old 01-14-2013, 02:27 PM #23
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The more I think about this the more wrong it becomes actually, lots of laws and formulas for how a compressed gas behaves that I forgot about a while ago. And my brain hurts trying to remember them.
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Old 01-14-2013, 04:46 PM #24
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a marker with a bolt of zero grams, zero friction, zero internal volume (including regulators, hoses, and chambers)
Where can I buy this?
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Old 01-14-2013, 05:04 PM #25
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Where can I buy this?
Brass Eagle
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Old 01-14-2013, 05:07 PM #26
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I think I found it



I can't wait to mow fools with this bad boy.
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Old 01-22-2013, 09:16 AM #27
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Originally Posted by speedy2k4 View Post
The more I think about this the more wrong it becomes actually, lots of laws and formulas for how a compressed gas behaves that I forgot about a while ago. And my brain hurts trying to remember them.
There are a ton of assumptions being made.
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Old 02-06-2013, 11:18 AM #28
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i'm right there with you.

good thread but i am sadly out matched here as much as i would like to be a part of this conversation.
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Old 02-07-2013, 12:12 PM #29
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Not bad.

But you've completely forgot about Entropy and Adiabatic Process.
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Old 05-09-2013, 11:00 PM #30
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this is cool ive always wondered what the max efficiency would be if the bolt was stationary with a nearly perfect reg and zero porting in the barrel i figured it would be higher though like 3K owell ha

bob longs coming pretty close with 17 pods off of a 68 in the insight NG so 17*140= 2380 dam hes getting close to no friction anywhere ha

dont mean to troll at all
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Old 05-10-2013, 08:39 AM #31
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You are negating far too many variables.
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